|
|
|
Sherril M. Stone, Ph.D. |
|
Department of Family Medicine |
|
OSU-College of Osteopathic Medicine |
|
|
|
|
|
Range |
|
highest score minus the lowest score |
|
Outliers will skew your data |
|
Interquartile Range Ð 25th, 50th, 75th, 90th,
etc 25th quartile Ð 25% of all scores fall below this score |
|
75th quartile Ð 75% of all scores fall below
this score |
|
Semi-interquartile Ð Q3ÐQ1 (middle 50%) Ð not affected by
outliers |
|
2 |
|
These are CRUDE MEASURES OF VARIABILITY - does
not tell the whole story about the raw data. A mean of 5.3 does not tell if
most of the scores were similar. So, we have measures of variability, which
tell us about the spread of the scores on the scale of measurement. |
|
Deviation |
|
the distance from the mean |
|
+ is above mean, - is below the mean |
|
Deviation scores - MUST sum (S) to zero |
|
|
|
|
|
Always report a measure of central tendency
(Mean & SD) and a measure of variability to describe a set of scores |
|
Variation (SS) = Sum of Squares |
|
Variance (s2
or S2) = SS/N (deviation scores squared/N) |
|
Standard deviation (s or SD) = square root of
variance |
|
Measures of variability provide a quantitative measure
of the degree to which scores in a distribution are spread out or clustered
together on the scale. |
|
If variance = 0 then all scores are the same, NO
variability exists |
|
If variance is large - then scores were very far
apart |
|
If variance is small Ð then scores were very
close together |
|
|
|
|
|
Variation, variance, and standard deviation |
|
measures of variability |
|
report these measures with the mean |
|
Population
Sample |
|
Variation: SS = S(X Ðm )2 SSx SSx |
|
Variance: SS/N = mean of SS
s2
s2 |
|
Standard Deviation: square root of s2 s s |
|
|
|
|
|
Definitional |
|
1. Find
N, SX,
and mean |
|
2. Subtract mean (X) from each X for deviation
score |
|
3. Square each deviation score (XÐ X)2 |
|
4. Sum the deviation scores S(X Ð X )2 =
SS (aka Variation) |
|
5. Variance (s2)
= SS/N |
|
6. S (SD) = SS/N |
|
Computational |
|
1. N, SX, and mean |
|
2. Square each data score |
|
3. Compute SS = S X2
- (SX)2 |
|
N |
|
4. Variance (s2) = SS/N |
|
5. S (SD) = SS/N |
|
|
|
|
X X - m (X - m)2 |
|
1 -1 1 N = 4 |
|
0 -2 4 m = 2 |
|
6 +4 16 |
|
1 -1 1 |
|
SX =
8 SX Ðm = 0 S(X Ðm)2 = 22 |
|
|
|
|
|
|
SX2
Ð (SX)2 |
|
s2 =
n |
|
N |
|
|
|
X X2 |
|
1 1 N = 4 |
|
0 0 X = 2 |
|
6 36 |
|
1 1 |
|
SX = 8 SX2 = 38 |
|
SS =
38 Ð 82/4 =
38 Ð 16 = 22 |
|
|
|
|
Samples tend to underestimate the population
data |
|
To correct sampling error we subtract 2 from n |
|
All scores are free to vary except 2 (e.g. when
you know all but 1 data score then it is determined) |
|
s2 = Sample variance = Sx2 = SS = 35.00 = 11.67 |
|
N-1 N-1 4 -1 |
|
|
|
s = Sample standard deviation = s2 = 11.67 = 3.42 |
|
|
|